10/2/2023 0 Comments Php if else if![]() The best equivalent to 'declaring' a php variable I could think of would just be to write: $number //This is NOT neededīut when you look at the code, it seems kind of strange to just write $number like that. ![]() In php, I believe, the memory is not allocated until something is actually stored in the variable. In Java, the computer allocates a 32 bit block of memory (the size of an int) when the variable is declared. Since php is dynamically typed, you can't write int $number. ![]() In php, however, there isn't really a way to do that. In Java, you have to declare a variable like this before using it in an if-then statement. For example in Java you can declare an 'int', then use it like so: int number In many programming languages you can "declare" a variable before you use it, just to let the compiler know that it's there. Here's a thought on why it works that way. If the if statement containing the variable was executed, then yes, you can access the variable outside of the if statement. To illustrate: if (true) var_dump(isset($d)) // falseįalse short circuits and the execution does not arrive at $d = 5, so the $d variable will not be defined.įor more about the PHP scope, read the variable scope manual page. So yes, if you define something inside the if statement or inside the block, then it will be available just as if you defined it outside (assuming, of course, the code inside the block or inside the if statement gets to run).
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